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recall: So, the essence of the situation is that the server and browser are functions with the type-signatures:The above is a lie. Let's look more closely.
server: stringurl → stringhtml
browser: stringhtml → void .
For this class, you'll need a browser with good debug-tools built in. For Firefox, there is an extension “Firebug”; I'll demo a couple of Chrome's built-in tools. We will not worry about supporting old browers (e.g. old versions of IE).
≡ » More Tools » Developer Tools
We'll look briefly at the "Elements" tab, but today we're mostly concerned with the "Network" tab,
and clicking on particular files.
In particular, viewing the Request Headers and Response Headers.
Together in class: Spend 15min looking at examples.
Btw, here are the official HTTP response codes, or the cat-picture version.
the real upshot: So, the essence of the situation is actually that the server and browser are functions with the type-signatures:
server: http-request-packet → http-response-packet (where the first packet contains the URL, and the second packet contains the html response);
browser: http-response-packet → void .
Further things to consider (if not today, then perhaps later:)
- ACTUAL: server-side computation (via Ajax): on each keystroke, a transaction is happening, and google.com computes the completion (for *every* google visitor in the world, yikes, is that a lot of bandwidth?) - What are some other *hypothetical* was this could be handled? - client-side: the server includes the top 10,000 most popular searches, and the client javascript uses that to determine the auto-completion. (This wouldn't explain the .) That would be an expensive load-time on every page! How might we use this approach but try to avoid having 'google.com' be a huge download every time? How about: only include that dictionary on the *first* visit to google.com, and have the client javascript write it to a file; then on subsequent visits this This requires something additional though: How does google know if this is the *first* time I'm visiting, or if I've visited previously and therefore I already have the set of common-searches cached? We'll discuss cookies later, which solve this.
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©2015, Ian Barland, Radford University Last modified 2016.Jan.19 (Tue) |
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